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Re: #32
Posted:
Jun 16, 2010 4:38 PM



hmmm.. actually what if x = 2? Then sq rt of (2)cubed = 2i sq rt 2. But if x = 2 and you are doing the sq rt of (2) squared that would still just be 2. I think. In which case you are right. I think. I'm rethinking all my math knowledge now!!  Original Message  From: TKENYON@crcs.wnyric.org To: nyshsmath@mathforum.org Sent: Wednesday, June 16, 2010 3:45 PM Subject: re: #32
Which is why is should be absolute value of x, because while you assume the positive square root (principal root), you don't know that x is positive  it was never indicated that the domain was positive values of x. (I'm not sure if we're in agreement, or doing two different things.)
when solving an equation x squared = 9, then yes the answer is + and  3, but when it is written as a square root, you assume the positive square root.
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