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Sharon
Posts:
427
From:
NYC
Registered:
6/26/05


Re: #32
Posted:
Jun 17, 2010 8:19 AM



Once again  we are debating and debating  so how can we expect the students to know how to do it?
Sharon
Original Message From: Roberta Silver <rsilver@pob.k12.ny.us> To: nyshsmath@mathforum.org; nyshsmath@mathforum.org Sent: Thu, Jun 17, 2010 8:16 am Subject: RE: #32
The answer is 8. You take the principal square root of 4 and cube it.
________________________________
From: ownernyshsmath@mathforum.org on behalf of Linda Restive
Sent: Wed 6/16/2010 4:46 PM
To: nyshsmath@mathforum.org
Subject: Re: #32
I mean 8 OR 8!! sorry.
 Original Message 
From: Linda Restive <mailto:precopio@nycap.rr.com>
To: nyshsmath@mathforum.org
Sent: Wednesday, June 16, 2010 4:41 PM
Subject: Re: #32
Along the same lines, what is the VALUE OF 4 ^ (3/2)? I have a book
that says 8 and 8.... but in another book they give the answer as only 8. It
seems even the authors are confused. I tried googling it but I get conflicting
answers.
 Original Message 
From: TKENYON@crcs.wnyric.org
To: nyshsmath@mathforum.org
Sent: Wednesday, June 16, 2010 3:45 PM
Subject: re: #32
Which is why is should be absolute value of x, because while you assume
the positive square root (principal root), you don't know that x is positive 
it was never indicated that the domain was positive values of x.
(I'm not sure if we're in agreement, or doing two different things.)
when solving an equation x squared = 9, then yes the answer is + and
 3, but when it is written as a square root, you assume the positive square
root.
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