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Topic: re: #32
Replies: 23   Last Post: Jun 18, 2010 5:18 AM

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 Sharon Posts: 427 From: NYC Registered: 6/26/05
Re: #32
Posted: Jun 17, 2010 8:19 AM
 att1.html (4.8 K)

Once again - we are debating and debating - so how can we expect the students to know how to do it?

Sharon

-----Original Message-----
From: Roberta Silver <rsilver@pob.k12.ny.us>
To: nyshsmath@mathforum.org; nyshsmath@mathforum.org
Sent: Thu, Jun 17, 2010 8:16 am
Subject: RE: #32

The answer is 8. You take the principal square root of 4 and cube it.

________________________________

From: owner-nyshsmath@mathforum.org on behalf of Linda Restive

Sent: Wed 6/16/2010 4:46 PM

To: nyshsmath@mathforum.org

Subject: Re: #32

I mean 8 OR -8!! sorry.

----- Original Message -----

From: Linda Restive <mailto:precopio@nycap.rr.com>

To: nyshsmath@mathforum.org

Sent: Wednesday, June 16, 2010 4:41 PM

Subject: Re: #32

Along the same lines, what is the VALUE OF 4 ^ (3/2)? I have a book

that says 8 and -8.... but in another book they give the answer as only 8. It

seems even the authors are confused. I tried googling it but I get conflicting

----- Original Message -----

From: TKENYON@crcs.wnyric.org

To: nyshsmath@mathforum.org

Sent: Wednesday, June 16, 2010 3:45 PM

Subject: re: #32

Which is why is should be absolute value of x, because while you assume

the positive square root (principal root), you don't know that x is positive -

it was never indicated that the domain was positive values of x.

(I'm not sure if we're in agreement, or doing two different things.)

when solving an equation x squared = 9, then yes the answer is + and

- 3, but when it is written as a square root, you assume the positive square

root.

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