On 2010-06-21, Peter Webb <webbfamily@DIESPAMDIEoptusnet.com.au> wrote: > "Tim Little" <email@example.com> wrote in message >> On 2010-06-21, Peter Webb <webbfamily@DIESPAMDIEoptusnet.com.au> wrote: >>> No, I only need a finite algorithm which will calculate it to n >>> decimal places with finite input. >> >> You have previously stated that you can do this with "about three >> lines of Java code". >> >> Here's your Java method signature: int antidiagonalDigit(BigInteger n). >> >> Here are the first twenty digits of the first twenty members of my >> list: >> >> 93525532854532512838 >> 32127313472944276266 >> 70595916184994935423 >> 20733652719572401688 >> 30472031767118774150 >> 47190325821263633948 >> 74236814853458351851 >> 58521903865615844550 >> 91701104659863267390 >> 39510921669610680229 >> 19656091025330568974 >> 49591084533660072011 >> 81683520683673830124 >> 93720622611168810054 >> 50284245443806050152 >> 11702670934156383526 >> 58534679962278312978 >> 68478827933494896765 >> 83579375050000862329 >> 50241229144880453593 >> >> Now let's see your Java code. > > Here is my p-code.
As I suspected, your claim that you could actually do it was pure puffery, and you probably know as little about programming as you do about mathematics.
> Take the nth digit of the nth item.
The n'th item of *what*? The list is not a parameter, it is not a global variable, it is completely out of scope. You fail already.