On 2010-06-23, Sylvia Else <email@example.com> wrote: > A1 is the antidiagonal of L1 L2 L3... > A2 is the antidiagonal of L1 A1 L2 L3... > A3 is the antidiagonal of L1 A1 L2 A2 L3 L4... > > Each An is thus constructed from a list that is different from the list > into which it is inserted. So the construction does not lead to a list > that should contain its own anti-diagonal
Yes. For this case there is a well-defined "limit" list L', with an antidiagonal A'. For all n, A' agrees with the first 2n-1 digits of A_n but disagrees at position 2n (and probably beyond). So A' is not in the limiting list L' (or any intermediate list).