"WM" <email@example.com> wrote in message news:firstname.lastname@example.org... > On 26 Jun., 00:32, "Mike Terry" > > > > Please let me know: Does the list consisting of A0, A1, A2, A3, ... > > > contain its antidiagonal or not? > > > > No, of course not. > > The set of all these antidiagonals A0, A1, A2, A3, ... constructed > according to my construction process and including the absent one is a > countable set.
Yes, I've agreed that several times.
> > > > > > > That is not a problem. It shows however, that there are countable sets > > > that cannot be listed. > > > > How exactly does it show that there are countable sets that cannot be > > listed? > > > See the one above: The results of my construction process.
No. The above shows that you've constructed a countable sequence of numbers (A0, A1, A2, A3,...) which CAN be listed, namely consider the list (A0, A1, A2, A3,...).
> > > > > OK, but you've still not given any explanation why you think the > > antidiagonals of your process cannot be listed! (I'm genuinely baffled.) > > You said so yourself, few lines above.
Rubbish. I have never said anything other than that (A0, A1, A2, ...) is a countable sequence of reals that CAN be listed.