
time as the circumference of the lobe inside the sphere: deriving speed of light from pure math Chapt 19 #217; ATOM TOTALITY
Posted:
Jul 8, 2010 4:04 PM


Archimedes Plutonium wrote: > Archimedes Plutonium wrote: > (rest snipped) > > > > So what I am imagining is that the pseudosphere is the time element > > whereas the sphere > > that encloses the pseudosphere inside is the distance element. And the > > distance is going > > to be for example Earthsphere of 40,000 km strips and 40,000 of these > > strips. So the > > speed of light is the distance light travels of 40,000 km x 40,000. > > And the time it takes for > > a light wave to travel that 1,600,000,000 km is 5,300 seconds. So > > where do I get 5,300 > > from the pseudosphere nested inside the sphere? I believe the 5,300 is > > Looking on page 73 of Seaborg & Loveland, 1990, The Elements Beyond > Uranium. > > Look at the cubic set with 8 lobes. Now what we can easily imagine is > the 8 lobes > switched around so that the fat portion of the lobe is in the center > of the cube > and the tip end is touching the 8 corners of the cube. Now let us > imagine removing > the cube and replacing it with the Sphere. Now, what I have in the > center of the > sphere are pseudospheres, 4 pseudospheres converted from the 8 lobes. > > Now imagine this sphere that has inside itself the 8 lobes turned > around and forming > 4 pseudospheres. Now I suspect I can get that number 5,300 when the > circumference > is 40,000, in that the circumference of one of those pseudospheres > largest circle is > 5,300. And as the size of the starting sphere is varied as such, the > corresponding > pseudosphere largest circle follows this pattern: > > > 60,000 x 60,000/ 12,000 = 300,000 > > > 50,000 x 50,000 / 8,300 = 300,000 > > > 40,000 x 40,000/ 5,300 = 300,000 > > > 30,000 x 30,000/ 3,000 = 300,000 > > > 20,000 x 20,000 / 1,300 = 300,000 > > > 10,000 x 10,000 / 330 = 300,000 > > The idea behind all of this is that the speed of light is a unison > effort of two geometries > elliptic and hyperbolic where distance comes from elliptic as 40,000km > x 40,000 and the > time factor comes from hyperbolic in that the circumference of the > largest circle is 5,300. > > Need to check all of this. For as the size of the sphere circumference > decreases, the circumference of pseudosphere largest circle must > decrease logarithmically. >
Alright the above makes logical sense, rather than the defect of the pseudosphere since its poles are cut off. Here, what I did was take two lobes from the Cubic Set shown on page 73 of Seaborg & Loveland's book "The Elements Beyond Uranium", 1990. So I have a pseudosphere nested inside a cube or sphere, in fact I have 4 pseudospheres, as I turn each lobe around and where the tip end meets the corners of the Cube and the lobe end meets each other and forming a pseudosphere. It is the circumference of this largest circle of the lobe ends.
So how does that fit together logically? It fits together in the idea that the LightWave is split into two parts, the distance part is the construction of the particle itself such as the sphere where the wave travels 40,000 km of 40,000 such strips and the second part is time in which it takes to cover those 40,000 x 40,000 is 5,300 which is the circumference of the largest circle of the lobes.
So that every cube can be turned into a sphere and inside that sphere are 8 lobes which are turned around to form 4 pseudospheres. So the distance of a Light Wave is the circumference of sphere x how many such strips divided by the time which is the circumference of largest pseudosphere circle.
So the speed of light is a fundamental constant or property of geometry, and is the relationship of how to construct a sphere given the time factor of the pseudosphere largest circle.
Important Note: someone complained that it should be for Earth's sphere of 40,000 km x 40,000 / 5,300 sec. Complained that it should be 1/2 of 40,000 since the strips when going around one complete revolution also absorb the strips on the other side so there is only 40,000 km x 20,000. I disagree and the best answer I can give now is that suppose we have the cubic set and not replace it with the sphere. Now the strips of the cube would cover up all the 4 sides if we used only 20,000 such strips, but if we used all 40,000 strips as in 40,000 x 40,000 then those two remaining sides of the full 6 sided cube are also covered up.
I guess I can explain why 40,000 is used on a sphere rather than 20,000 is that we really do not know where the light wave is within that 1 km wide strip and so when we circumnavigate on the Equator we must have 40,000 strips and not 20,000, not knowing if the light wave is directly in the center of each strip or off on a side of the center.
Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electrondotcloud are galaxies

