h.jones
Posts:
32
From:
uk
Registered:
2/21/08


Re: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Posted:
Nov 28, 2010 1:21 PM


Another interesting area for symmetries is the SI gravitational system, particularly in the area of GM products. The GM product is necessary because we cannot weigh large spheres of mass but we can measure them and it is by linear measurement and through the inherent local gravitational effects that we can deduce the GM product. The time unit of our system is the second and the time scale mass of our system is 1.0095x10^35Kg (designated by large M in formulae here). That is the particular mass where the Schwarzshild diameter is equal to one light second. The GM product of this particular mass is 6.7360006x10^24. This is equal to 2(c/2)^3. There is an interesting numerical quirk involved with the timescale mass M and G the gravitational constant. If you multiply it by the Planck Mass squared, small m^2, you get the following results: Mm^2=7.51324x10^19. If you multiply this by G you get 5.01329x10^9. I call this n, n for neither, neither quantum nor G. If you multiply n with G, Gn, you wind up with 3.345x10^1, reciprocal=2.9893. The square root of 2.8983=1.72898 and the GM product 6.736x10^24x1.72898=1.16464x10^25 which is the square root of c^2/h, which is the Compton frequency of the kilogram per second. If you multiply h(c/2)^4 you again get Gn or 3.345x10^1 thus proving a link with the quantum world and G. What is evident here is that the concept of G and GM products as separate scaled entities from the mass unit base, in our case the kilogram, is older than Mankind. The inventions of the second and the metre are three and a half thousand years apart so for the SI system to be out by a factor of 1.72898 is an amazing coincidence. This makes the altered metre (1.72898)^0.333r smaller than it is and c would then be 1.2 greater at 3.59819x10^8 and the GM product at 2x(c/2)^3 would once again be equal to 1.16464x10^25. Gm^2 would be 1/(1.16464x10^25. G, the gravitational constant, would then be 1/(Mm^2)^0.5. Or, 1/(7,51324x10^19)^0.5.=1/ (8.6679x10^9)=1.15368x10^10, and, (1.16464x10^25)/ (1.1536x10^10)=1.0095x10^35Kg. Nature will always find a way to symmetrise even in the most unlikely numerical scenario. Mind you it would play havoc with the litre and its link to the kilogram.

