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Topic: A191837
Replies: 13   Last Post: Jul 12, 2011 1:43 PM

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a-user

Posts: 24
Registered: 6/5/11
Re: A191837
Posted: Jul 5, 2011 12:02 AM
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For any m=2*prime, m-(m/2) = m/2 = prime. So why does p[2n] need to be strictly less than m/2?



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