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Re: f(z) + abs(z) = 0, where z is complex
Posted:
Jul 10, 2011 3:16 PM


slawek <human@site.pl> schrieb: > I am looking for a numerical solution of f(z) + abs(z) = 0, where z is a > complex number and f is the analytic function. > > Newton method does not work, because there is no derivative of the > nonanalytic abs(z).
Take z = x + I*y, split f(x) into its real part f1(x,y) and its imaginary part I*f2(x,y), then calculate the zeros of the functions
f1(x,y)  sqrt(x^2+y^2) f2(x,y)
using a twodimensional Newton method.



