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slawek
Posts:
25
Registered:
12/12/08


Re: f(z) + abs(z) = 0, where z is complex
Posted:
Jul 10, 2011 3:35 PM


U?ytkownik "Thomas Koenig" napisa? w wiadomo?ci grup dyskusyjnych:ivctqv$3f7$1@newsreader4.netcologne.de...
>Take z = x + I*y, split f(x) into its real part f1(x,y) and its >imaginary part I*f2(x,y), then calculate the zeros of the >functions
>f1(x,y)  sqrt(x^2+y^2) >f2(x,y)
>using a twodimensional Newton method.
It should work, but I think that the substitiution z = abs(z) exp(i Arg(z)) would help a little.



