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Re: f(z) + abs(z) = 0, where z is complex
Posted:
Jul 10, 2011 7:45 PM


On 7/11/2011 7:06 AM, slawek wrote: > U?ytkownik "Gordon Sande" napisa? w wiadomo?ci grup > dyskusyjnych:ivcrqr$f5g$1@dontemail.me... > > On 20110710 15:24:35 0300, slawek said: > >>> I am looking for a numerical solution of f(z) + abs(z) = 0, where z >>> is a complex number and f is the analytic function. >>> >>> Newton method does not work, because there is no derivative of the >>> nonanalytic abs(z). >>> >>> TIA >>> slawek > >> What happens if one considers f(x,y) insead of f(z) and >> sqrt(x^2+y^2) instead of abs(z) and uses a method suitable >> for two real variables? > > We will have got two variables and only one equation.
You have two equations, the real part and the imag part.



