Drexel dragonThe Math ForumDonate to the Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by Drexel University or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math.num-analysis.independent

Topic: f(z) + abs(z) = 0, where z is complex
Replies: 18   Last Post: Jul 11, 2011 9:23 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Gib Bogle

Posts: 42
Registered: 3/28/11
Re: f(z) + abs(z) = 0, where z is complex
Posted: Jul 10, 2011 7:45 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On 7/11/2011 7:06 AM, slawek wrote:
> U?ytkownik "Gordon Sande" napisa? w wiadomo?ci grup
> dyskusyjnych:ivcrqr$f5g$1@dont-email.me...
> On 2011-07-10 15:24:35 -0300, slawek said:

>>> I am looking for a numerical solution of f(z) + abs(z) = 0, where z
>>> is a complex number and f is the analytic function.
>>> Newton method does not work, because there is no derivative of the
>>> non-analytic abs(z).
>>> TIA
>>> slawek

>> What happens if one considers f(x,y) insead of f(z) and
>> sqrt(x^2+y^2) instead of abs(z) and uses a method suitable
>> for two real variables?

> We will have got two variables and only one equation.

You have two equations, the real part and the imag part.

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© Drexel University 1994-2014. All Rights Reserved.
The Math Forum is a research and educational enterprise of the Drexel University School of Education.