
Re: dirac delta function is not a TRUE function??
Posted:
Jul 14, 2011 12:22 PM


In article <9f2192a597764c559a2deeb93f0559ab@g3g2000prf.googlegroups.com>, MBALOVER <mbalover9@gmail.com> writes: >On Jul 11, 7:36=A0pm, Gerry Myerson <ge...@maths.mq.edi.ai.i2u4email> wrote: >> In article <4c1e3a1663c5470ab6178528f4005...@u6g2000prc.googlegroups.com>, =A0MBALOVER <mbalov...@gmail.com> wrote:
>> > From WIKI, I learn that dirac delta function is not a true function.
>> > Could you please help me to understand it?
>> A function from a set A to a set B is an assignment of >> an element of B to each element of A. >> >> If A and B are not specified, it is often assumed that both >> are taken to be the set R of real numbers. >> >> The Dirac delta function does not assign a real number to zero, >> and is thus not a true function.
>Thanks Gerry. But I am still confused. I think at x =3D 0, delta(x) = >infinity.
That's one way of looking at it  in fact it's the one that I was taught while studying electical engineering. However, look more carefully at what was said: "... does not assign a real number to zero ...".
There is no real number called "infinity".
 Michael F. Stemper #include <Standard_Disclaimer> If you take cranberries and stew them like applesauce, they taste much more like prunes than rhubarb does.

