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Re: dirac delta function is not a TRUE function??
Posted:
Jul 14, 2011 12:22 PM
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In article <9f2192a5-9776-4c55-9a2d-eeb93f0559ab@g3g2000prf.googlegroups.com>, MBALOVER <mbalover9@gmail.com> writes:
>On Jul 11, 7:36=A0pm, Gerry Myerson <ge...@maths.mq.edi.ai.i2u4email> wrote:
>> In article <4c1e3a16-63c5-470a-b617-8528f4005...@u6g2000prc.googlegroups.com>, =A0MBALOVER <mbalov...@gmail.com> wrote:
>> > From WIKI, I learn that dirac delta function is not a true function.
>> > Could you please help me to understand it?
>> A function from a set A to a set B is an assignment of
>> an element of B to each element of A.
>>
>> If A and B are not specified, it is often assumed that both
>> are taken to be the set R of real numbers.
>>
>> The Dirac delta function does not assign a real number to zero,
>> and is thus not a true function.
>Thanks Gerry. But I am still confused. I think at x =3D 0, delta(x) =
>infinity.
That's one way of looking at it -- in fact it's the one that I was
taught while studying electical engineering. However, look more
carefully at what was said: "... does not assign a real number to
zero ...".
There is no real number called "infinity".
--
Michael F. Stemper
#include <Standard_Disclaimer>
If you take cranberries and stew them like applesauce,
they taste much more like prunes than rhubarb does.
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