quasi
Posts:
12,067
Registered:
7/15/05


Re: a contradiction worth reading (unless a silly mistake was made)
Posted:
Jul 22, 2011 6:32 PM


On Fri, 22 Jul 2011 17:50:35 0500, quasi <quasi@null.set> wrote:
>On Fri, 22 Jul 2011 16:11:22 0500, quasi <quasi@null.set> wrote: > >>Conjecture: >> >>If p is prime with p = 3 (mod 4) and (p1)/2 also prime, then >>for all integers x,y with x,y not congruent to 0,1,1 (mod p), >> >>the sets >> >> {x^(2^i) (mod p), i = 1,2,3, ...} >> >> {y^(2^j) (mod p), j = 1,2,3, ...} >> >>have the same number of elements. > >It's true  I can prove it. > >But for now, I'll leave it as a challenge.
To Simon Roberts:
The above result, while elementary, is (I think) interesting and not entirely trivial, so your ideas did lead to something worthwhile.
quasi

