I instead give you a rule which will cover all of them with the same number: A real that is missing from your first list has a 1 in its nth position if your nth digit in the nth number is 2 and has 2 there otherwise.
This will produce a number missing from your first listing.
Since each of your listings contains exactly the same set of numbers, merely permuted as to ordering, whatever is missing from any one of them will be missing from all of them.