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Topic: Matrix dimensions must agree
Replies: 7   Last Post: Oct 20, 2011 2:30 PM

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Halley

Posts: 5
Registered: 10/20/11
Matrix dimensions must agree
Posted: Oct 20, 2011 11:11 AM
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I am trying to write a program that utilizes the inverse iterative method. I calculate an initial x value and rho value given the matrices A, B, and b. I calculate a value of x normalized to the matrix B (xnorm) as well as a new value for rho for each iteration. Given that the relative error of rho is less than my preset tolerance (TOL) the loop ends, otherwise xnorm becomes the new value for x and the rho(i+1) becomes rho(i). The problem is in calculating rho(i), I am told my matrix dimensions do not agree when I have checked the sizes multiple times. Any suggestions? Thanks.

%Declare initial variables
A = [2 -1;-1 4];
b = [1;1];
B = [1 0;0 1];
Nmax = 20;
TOL = 1*10^-5;
k = 1;
x = zeros(2,21);
x_a = zeros(21,2);
rho = zeros(21,1);
xnorm = zeros(2,21);
x(:,1) = A\b;
x_a(1,:) = x(:,1)'

for i =1:Nmax

%Calculate old values
rho(i) = (x_a(i,:).*A.*x(:,i))./(x_a(i,:).*B.*x(:,i))

%Calculate new values
xnorm(:,i) = (1/sqrt(x_a(i,:).*B.*x(:,i))).*x(:,i)
rho(i+1) = (x_a(i,:).*A.*x(:,i))./(x_a(i,:).*B.*x(:,i))

%Check for convergence
relative_error = abs((rho(i+1)-rho(i))/rho(i+1))

if ( relative_error ~= 0 && relative_error <= TOL )
x(i+1) = xnorm(i)
rho(i+1) = rho(i+1)
k = k
return
elseif (relative_error ~= 0 && relative > TOL)
x(i+1) = xnorm(i)
rho(i) = rho(i+1)
k = k+1

end
end



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