
Re: Ariadne's thread
Posted:
Nov 26, 2011 2:22 AM


John E. Clark found an amazing number of calendar measurements in the sacred precinct of Tenochtitlan, published in the paper: Aztec dimensions of holiness, in The Archaeology of Measurement (op.cit.), and gives a long list of Aztec body measures. I linked them with numbers of concordance, at the begin of each line; at the end of some lines, in brackets, measures from Clark.
30  finger (1.74 cm) 240  half a foot 310  jeme 360  palm of the hand 480  foot print (27.86 cm) 576  bone 660  forearm 720  elbow 1200  step 1240  armpit 1335  shoulder (77.5 cm) 1440  heart / vara (83.59 cm) 2160  arrow, dart (1.254 m) 2760  stature, height of a man 2880  hand, horizontal braza 4320  wooden measuring rod 4800  ten feet (2.786 m)
16 fingers are one foot, 48 fingers or 3 feet are one vara. If the diameter of a circle measures 5 shoulders, the circumference measures 6 shoulders 6 arrows, value of pi 1398/445 from the sequence
12/4 (plus 22/7) ... 1398/445 1420/452
The measures * arrow minus shoulder * shoulder * arrow * arrow plus shoulder * form a golden sequence, 55 89 144 233. John E. Clark postulates the presence of the golden section at Tenochtitlan.
If the side of a square measures 15 shoulders, the diagonal measures 6 ten feet minus 1 foot, and if the diagonal measures 6 ten feet minus 1 foot, the diagonal measures 30 shoulders, values for the square root of 2 1888/1335 and 1335/944 respectively.
If a square measures 150 by 150 shoulders, the diagonal measures 59 ten feet, and the circumfernce 180 shoulders 180 arrows.
The base of the pyramid and Templo Mayor at Tenochtitlan might ideally measure 100 by 105 shoulders (calculated from the map), diagonal 145 shoulders, basic triple 202129. The quasisquare 100 by 105 may contain an imaginary divine square 100 by 100 shoulders and the inscribed circle of the circumference 120 shoulders 120 arrows.
The Aztecs might have calculated the circle on the basis of the number 29 and the first triple 202129, second triple 41840841. The second polygon is a quasisquare of 12 short and 8 long sides. If the arc of the short side is 41 and the arc of the long side 599, the circumference of the rounded polygon is 5284. 5284 divided by the diameter 2642 yields 2642/841 for pi, from the sequence
3/1 (plus 377/120) ... 1888/601 ... 2642/841

