Marshall
Posts:
1,928
Registered:
8/9/06
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Re: Eliminating Quantifiers For Dummies! A(x) E(y) ALL(t)EXIST(u)EaAb ..
Posted:
Jan 23, 2012 11:21 PM
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On Jan 23, 7:52 am, Dan Christensen <Dan_Christen...@sympatico.ca> wrote: > On Jan 23, 10:23 am, Alan Smaill <sma...@SPAMinf.ed.ac.uk> wrote: > > > > > > > > > > > Jack Campin <bo...@purr.demon.co.uk> writes: > > >> > There is a decision procedure for equality of terms in the first > > >> > order theory of Abelian groups (and for a lot of other subtheories > > >> > of the first order theory of groups). > > > >> > Express the same problem in your language and there isn't one. > > > >> Why not? If there's a decent translation of the original statements > > >> into statements in the DC version of abelian group theory, and DC is > > >> complete, then there's still a decision procedure for the translated > > >> statements. > > > >> No decision procedure for arbitrary statements in DC, I agree. > > > > The problem is identifying which expressions in DC are suitable > > > inputs for a decision procedure (rewrite rule system, say). You're > > > only going to be able to do that if you know enough to reconstruct > > > their equational forms. If you don't even recognize the existence > > > of a first-order group theory sublanguage in your calculus, this is > > > going to be difficult. > > > As long as you have a decent translation, then the image of that > > translation gives you the statements you are interested in. > > I can't see any serious issue in describing such a translation -- > > in fact there are steps in that direction elsewhere in the thread. > > > > The examples DC has given include no more > > > than assertions of membership in a single carrier set, and they > > > can just be thrown away, but in principle things can get much more > > > complicated. > > > Yes, in principle -- but that complication doesn't affect the > > decidability of the validity of the translated inputs. (The set theory > > needed would be minimal anyway, presumably) > > Sorry, no set theory at all for Jack! In his first-order group theory, > Jack will not even admit "0 in G." No "elements of a set." No > underlying sets and no implicit domains of quantification. His first- > order group theory is to be completely untainted by ANY set-theoretic > considerations whatsoever, right, Jack? Am I wrong? I really hope so.
And that's not all! Jack also doesn't have any group-theoretic considerations in his set theory!
Hey, how come DCProof doesn't have any image editing tools in it? Not even a simple pencil drawing tool. Why is that?
Marshall
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