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Re: X, Y and Z Interferometer Update
Posted:
Jan 24, 2012 10:33 PM
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most avionics is based these days upon little rings of fiber-optic, I believe one around each of the roll, pitch & yaw axes of the plane; these are interferometers, and presumbaly the whole of the Michelson-Morley experiments can be done with these little boxes. incidentally, it is not true that they had no result; the small, annual anomaly was measured repeatedly, as well as been verfied by others, D.C.Miller e.g., probably most consonant "at the time" with "aether drag.
not that there is any need, at all, for any aether other than the nucleii, electrons and diatomic (uncharged with no dipole) molecules, like H2, which is about an order of magnitude more, out there, than ionic H+ (taht is, elsewhere than stars).
Good Will Hunting is about your speed, dood!
> The ?Update? referred to in the title of this post regards my > realization that the PULSING light seen on the paper target as my > interferometer is being rotated has a mathematical, harmonic cause. > Some of you out there might like to calculate the number of fringe > shifts that are uniformly occurring in each one of those pulses. It > would then be quite easy for me to calculate the number of pulses in > 360 degrees of apparatus rotation.
> interferometers will allow space ships to precisely determine their > speed and course without once needing to look out at the stars nor to > check a spinning gyroscope!
> The known helium-neon laser passes out of the 1 mm pin hole in a > narrow cone of light. That cone, in the control light course has a > SHORTER distance of travel back to the target than does the TEST light > course that travels about two feet further back to the target (six > feet of travel vs. eight feet of travel). The latter disparity means > that the ?component? bulls eye (which is not yet a visible light and > dark fringe) will be 33.33% bigger (more blown-up in scale) for the > TEST light course, than for the control. *** The maximum brightness > of the pulses on the target will occur when there are the LEAST number > of dark bands on the target, and the maximum number of light bands. > By making a computer graphic of the target bulls eye, which occurs in > just a nominal 3/8? circle centered on the pin hole, the motion of the > two different fringe ?components? should be able to be plotted and the > number of fringe ?component? shifts necessary to cause the pulses can > be calculated. > > I realize that doing the above harmonic pulse calculation could well > require a ?Good Will Hunting? level of mathematical proficiency.
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