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Re: Operations with algebraic fractions assistance please
Posted:
Jan 30, 2012 8:33 AM


You might also mean (putting the parentheses differently) (5/x+ 6/x^2)/(25/x^2 36/x)
First do the numerator and denominator separately: add 5/x+ 6/x^2. The least common denominator is x^2: 5x/x^2+ 6/x^2= (5x+ 6)/x^2.
Add 25/x^2 36/x= 25/x^2 36x/x^2= (25 36x)/x^2.
Now, "invert and multiply": [(5x+ 6)/x^2][x^2/(25 36x)] The x^2 terms cancel leaving (5x+ 6)/(25 36x)



