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Topic: Operations with algebraic fractions assistance please
Replies: 2   Last Post: Jan 30, 2012 8:33 AM

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George Ivey

Posts: 9
From: here
Registered: 1/30/12
Re: Operations with algebraic fractions assistance please
Posted: Jan 30, 2012 8:33 AM
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You might also mean (putting the parentheses differently) (5/x+ 6/x^2)/(25/x^2- 36/x)

First do the numerator and denominator separately: add 5/x+ 6/x^2. The least common denominator is x^2: 5x/x^2+ 6/x^2= (5x+ 6)/x^2.

Add 25/x^2- 36/x= 25/x^2- 36x/x^2= (25- 36x)/x^2.

Now, "invert and multiply":
[(5x+ 6)/x^2][x^2/(25- 36x)]
The x^2 terms cancel leaving (5x+ 6)/(25- 36x)



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