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Re: Why not Hausdorff's ordered pairs
Posted:
Feb 23, 2012 2:45 PM
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On Feb 24, 1:30 am, Zuhair <zaljo...@gmail.com> wrote:
>
> > None of these work!
>
> OF course they work, why you think I wrote them?
>
> > You are confusing { (1, a), (2, b), (3, c) } with { {1, a}, {2,
> > b}, {3, c} }
>
> No I am not, you are simply BLIND read well what I wrote
> I didn't wright { {1,a} , {2,b} , {3,c} } as you said
<UNSNIP>
Define <a,b>={{1,a},{2,b}}
> I wrote { {1,{a}} , {2,{b}} , {3,{c}} } which is different
Same bullshit.
> It seems that you don't know the difference between
> {1,a} and {1,{a}}. My version works I am sure of that
a = dummy
a = {dummy}
Same dummy!
> I already have tested it, it works nicely as a tuple, it is
> stratified and it can be generalized to any length n,
> it is simple and admites the simples projection definition
> among all n-tuples for a general n. You only missed the point.
> Read well before responding!
I'm not going to correct you with the same correction a 4th time.
> > What is the order here?
>
> > { {4, 1}, {1, 2}, {2, 3}, {3, 4} }
If you bothered to answer the question you would see your error.
>
> > <2 3 4 1> or <4 1 2 3> ?
>
> > ***********************************************************
>
> > You have to nest the braces outside of the ordered pair.
>
> > { {a,{}} , {{b,{}}} , {{{c,{}}}} , {{{{d,{}}}}} }
>
> > Now (a, a) = { {a,{}}, {{a,{}}} }
>
> > has 2 full elements, no singleton!
>
Herc
--
http://Matheology.com
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