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Re: Inversion Lerch Phi
Posted:
Apr 19, 2012 1:09 PM
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Did schrieb: > > On 4/12/12 7:15 PM, clicliclic@freenet.de wrote: > > > > Did schrieb: > >> > >> I am wondering if there is exist an inversion > >> formula for the Lerch transcendent Phi(x,s,a) > >> similar to the inversion of the polylogarithms. > >> > >> More precisely, I would like to simplify the > >> expression > >> > >> Phi(z,s,a) +/- (-1)^s * Phi(1/z,s,-a) = ??? > >> > >> at least for s=1. The ??? should be an > >> expression easier to compute than Phi. > >> > > > > Looks like you want a correct version of Gradshteyn&Ryzhik formula > > 955.2, taken from Erdelyi. I believe the relation was first derived by > > Lerch in his Note sur la fonction K(w,x,s) = SUM(e^(2*k*pi*i*x)/(w+k)^s, > > k, 0, inf) in Acta Math. 11 (1887), 19-24. Lerch probably didn't care > > much about branch cuts, and Erdelyi then got it definitely wrong. > > > > But a correct version exists indeed: it is leading a pieceful life in my > > vaults. Let's see if somebody can come up with it within a week! And > > provide a proof within another week! > > > > Thanks Martin, I was actually expecting a reply from you ;-) > > Branch cuts do indeed matter to me, specially that I have to > deal with the possibility |z|>1 (but a is real and not an integer). > However, for now, I need only s=1 and the plus sign, but it is > interesting to know the general case, if it exists. > > In fact, it's the equivalent formula for the Lerch zeta-function > I'm the most interested in. (That should be straightforward to > pass from one to the other, unless I'm missing something about > the branch cuts.) > > Looking forward to see if somebody can come up with it within > a week!!! >
One bright Sunday morning I went to church, And there I met a man named Lerch. We both did sing in jubilation, For he did show me a new equation.
- Bruce C. Berndt, 1972.
One week has passed and I don't want to tax your patience any longer. The following corrected version of Gradshteyn&Ryzhik formula 9.552 is in my vaults:
Phi(z,s,v) = (-z)^(-v) (2 pi)^(s-1) Gamma(1-s) [i^(1-s) e^(-i pi v) Phi(e^(-2 pi i v), 1-s, 1/2 + ln(-z)/(2 pi i)) + i^(s-1) e^(i pi v) Phi(e^(2 pi i v), 1-s, 1/2 - ln(-z)/(2 pi i))] [either Im(v) < 0, 0 < Re(v) <= 1 or Im(v) >= 0, 0 <= Re(v) < 1].
For s=0, the right-hand side involves something like x*Phi(x, 1, 1/2+y) - Phi(1/x, 1, 1/2-y) and you have to use G&R formula 9.551 to increase or decrease the third Phi argument by one. The left-hand side becomes Phi(z, 0, v) = 1/(1-z), independent of v.
The proof of this formula for complex z,s,v is left to the sci.math.symbolic public, however.
Martin.
PS: The Maple documentation for LerchPhi(z,s,v) doesn't explicitly say whether the branch cut for z>1 is to the right or to the left of the real axis.
<http://www.maplesoft.com/support/help/Maple/view.aspx%3Fpath%3DLerchPhi>
Here are some Derive results for my implementation on the real axis:
VECTOR([z, lerch(z, 1, 1/2)], z, 0, 2, 1/4)
[[0, 2], 0.25, 2.197224577], 0.5, 2.492900959], 0.75, 3.041383984], 1, ?], 1.25, 2.582453645 - 2.809925892*#i], 1.5, 1.87176262 - 2.56509966*#i], 1.75, 1.491669994 - 2.374820823*#i], 2, 1.246450479 - 2.221441469*#i]]
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