|
|
Re: 0^0=1
Posted:
Apr 21, 2012 3:30 PM
|
|
DonH wrote:
>
> "Frederick Williams" <freddywilliams@btinternet.com> wrote in message
> news:4F92FE5B.D2586615@btinternet.com...
> > DonH wrote:
> >>
> >
> >>
> >> # If x^(a+0) = x^a, then the implication is that x^0 = 0; the x^0 is
> >> dedundant.
> >
> > x^a = x^(a+0) = x^a x^0 rather implies that x^0 = 1.
>
> # Does it? Maths' Order of Operations states that parenthesis is evaluated
> first, which reduces (a+0) to a; leaving only x^a. Hence, x^0 = 0.
p^(q+r) = p^q p^r
--
When a true genius appears in the world, you may know him by
this sign, that the dunces are all in confederacy against him.
Jonathan Swift: Thoughts on Various Subjects, Moral and Diverting
|
|
