|
|
Re: 0^0=1
Posted:
Apr 22, 2012 9:34 AM
|
|
Pubkeybreaker wrote:
>
> On Apr 22, 2:22 am, Dave <dave_and_da...@juno.com> wrote:
> >
> > Whether x^a is complex or undefined when x < 0 and a is irrational depends on whether you say that sqrt(-1) is undefined or i, doesn't it?
>
> No, it doesn't.
Well, I'm not so sure. If "you say" that sqrt(-1) is undefined, then
that implies that reals only are being considered; and in that case, if
x^a were (non-real) complex, then it would be undefined.
--
When a true genius appears in the world, you may know him by
this sign, that the dunces are all in confederacy against him.
Jonathan Swift: Thoughts on Various Subjects, Moral and Diverting
|
|
