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Re: 0^0=1
Posted:
Apr 23, 2012 12:45 AM
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Dan Christensen writes:
> I have always informally justified 0^0 being undefined as follows:
>
> x^0 = x^(1-1) = x^1 / x^1 = x/x is undefined for x=0
Then x^n is undefined for any n at x = 0. Think x^3 = x^4 / x^1.
Then I suppose also 0 * 0 is undefined since it's 0^2. And 0 itself is
undefined since it's 0^1. And 0 * x is undefined for all x since it's
(0 * x)^1 = 0^1 * x^1.
I suggest you don't want to follow your own argument after all.
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