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Re: variation on a familiar calculus problem
Posted:
May 3, 2012 10:23 AM
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>The problem could have said 2 sides in which case you would arrive at a right isosceles triangle which when added to its mirror image would be a square (with the wall running across its diagonal)
Why would one not start then with a equilateral triangle and half that?
Anyway, I'm not questioning your instincts. However, I think the type of reasoning I'm outlining works without one even knowing about the special properties of circles and squares in advance.
Joe N.
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