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Re: 0^0=1
Posted:
May 6, 2012 3:54 PM
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In article
<7660332.3453.1336328461957.JavaMail.geo-discussion-forums@vbbfk16>,
PotatoSauce <kiwisquash@gmail.com> wrote:
> On Sunday, May 6, 2012 2:07:09 PM UTC-4, Jussi Piitulainen wrote:
> > LudovicoVan writes:
> > > Jussi Piitulainen wrote in message
> > > news:qotehqxw7ot.fsf@ruuvi.it.helsinki.fi...
> > > > LudovicoVan writes:
> > >
> > > >> (I'll talk about 0/0 because 0^0 can be shown to be equivalent.)
> > > >
> > > > How?
> > >
> > > I'll let you find that out (hint: what is x^0?), it is anyway
> > > immaterial to the generality of the point I have made.
> >
> > x^0 = 1 for all x, which is consistent with 0^0 = 1.
> >
> > You are clearly unable to show that 0/0 and 0^0 are somehow
> > equivalent, and you are unable to show that 0^0 = 1 has any
> > undesirable consequences at all. That is the whole point.
>
> My guess is that
>
> 1) He is writing
>
> 0^0 = 0^(1-1)=0^1 0^{-1} = 0/0
Using this logic, then 0^3 is undefined since:
0^3 = 0^(6-3)=0^6 0^{-3} = undefined since0^{-3} is undefined.
>
> or
>
> 2) He meant "0^0 = 1 is equivalent to 0/0 = 0" but messed up the second
> equality.
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