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Re: Calculating 1st derivative with a parameter
Posted:
May 6, 2012 12:25 PM
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"Angie" wrote in message <jo689r$idb$1@newscl01ah.mathworks.com>...
> "Wojtek" wrote in message <jo61cj$m95$1@newscl01ah.mathworks.com>...
> > Hello,
> > in my program I want to calculate the 1st derivative of a function y (it's a function of 'x1'). Let's say I want to check if the 1st derivative of this function in some specific point is smaller then 0.05. I have:
> >
> > syms x1;
> > y = ( x1 - za )*( x1 - zb )*( x1 - zc )*( x1 - zd ); %my function, all the parameters like 'za' were previously declared
> >
> > dydx=diff(y,x1,1);
> >
> > x_val=1;
> > dydx_val=subs(dydx,x1,x_val);
> > k2 = solve(dydx_val);
> > dydx_val =double(k2);
> >
> > if (dydx_val<0.05)
> > remember=x_val;
> > end
> >
> >
> > unfortunately the derivative is not calculated. I get information:
> > Warning: 1 equations in 0 variables.
> > Warning: Explicit solution could not be found.
> > and when I try to display dydx_val i get:
> >
> > dydx_val =
> >
> > []
> >
> > I tried different methods, none of them was good (although I could do something wrong). I will be grateful for suggestions how can I calculate 1st derivative in a specific point and have the value of this derivative in double.
>
> Hello,
>
> If I understood your question correctly, you don't need the line for solve and the following seems to work for me:
>
> syms za zb zc zd x1;
> y = ( x1 - za )*( x1 - zb )*( x1 - zc )*( x1 - zd );
>
> xVal = 1;
>
> % Take the derivative and substitute the value of x1
> focValue = subs(diff(y,'x1'),x1,xVal);
>
> if focValue < 0.5
> remember = focValue;
> end
>
> I hope this helps,
>
> A.
Correction and I forgot to mention something else:
0.05 instead of 0.5 and I assume you have numerical values for your za,zb,zc,zd parameters. In other words, if you put numerical values for za,zb,zc,zd (instead of syms za zb ...) you should be able to get your result.
A.
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