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Topic: 0^0=1
Replies: 145   Last Post: Jun 5, 2012 1:10 PM

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Re: 0^0=1
Posted: May 28, 2012 7:27 AM

Michael Press <rubrum@pacbell.net> wrote:
> In article <zKpkr.6017\$%E2.342@viwinnwfe01.internal.bigpond.com>,
> "DonH" <donlhumphries@bigpond.com> wrote:
>

>> "Richard Tobin" <richard@cogsci.ed.ac.uk> wrote in message
>> news:jmsvh1\$nml\$1@matchbox.inf.ed.ac.uk...

>>> In article
>>> Tonico <Tonicopm@yahoo.com> wrote:
>>>

>>>> Or, since we're dealing with real or complex numbers, consider lim x^x
>>>> = lim e^{x log(x)} , when x --> 0 ...this is a good reason to define
>>>> 0^0 = 1 .

>>>
>>> But equally one could consider the limit of 0^x.
>>>
>>> For integers the set mapping argument seems compelling, but when
>>> dealing with the reals it seems better to leave it undefined or define
>>> it explicitly if needed.

>>
>> # Yes, 0^0 may be an arbitrary device to accommodate a computer, as Barron's
>> Maths Study Dictionary excludes zero(^0) (pg.62) when defining the "zero
>> exponent".
>> Which still leaves, eg. 5^0 = 1.
>> If I have five apples and multiply them by themselves zero times, do I
>> end up with one apple?

>
> You get 1 apple^0 = 1; so you get no apples.

X^0=0?

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