
Re: Flattening a hypermatrix into an ordinary matrix
Posted:
Jun 2, 2012 5:45 AM


On Jun 1, 2:21 am, car...@colorado.edu wrote: > I have an n x n hypermatrix, the entries of which are m x m blocks. > For example A below (m=3, n=2): > > A11={{B11,B12,B13},{B21,B22,B23},{B31,B32,B33}}; > A12={{C11,C12,C13},{C21,C22,C23},{C31,C32,C33}}; > A21={{D11,D12,D13},{D21,D22,D23},{D31,D32,D33}}; > A22={{E11,E12,E13},{E21,E22,E23},{E31,E32,E33}}; > A={{ A11,A12},{A21,A22}}; > > I want to convert this to an ordinary n*m x n*m matrix. > For the example I want A to become > > {{B11,B12,B13,C11,C12,C13},{B21,B22,B23,C21,C22,C23}, > {B31,B32,B33,C31,C32,C33},{D11,D12,D13,E11,E12,E13}, > {D21,D22,D23,E21,E22,E23},{D31,D32,D33,E31,E32,E33}} > > This can be easily done with C style loops as > > AA=Table[0,{m*n},{m*n}]; > For [i=1,i<=n,i++, For[j=1,j<=n,j++, > For [k=1,k<=m,k++, For [l=1,l<=m,l++, > AA[[m*(i1)+k,m*(j1)+l]]=A[[i,j,k,l]] > ]]]]; > > but is there a more elegant way using Flatten? > (Flatten[A,1] doesnt do it.) It should work also for blocks > of varying size for future use.
Flatten /@ Flatten[Transpose[A,{1,3,2,4}],1]
will also do it and is a little cleaner than my previous suggestion.

