
Re: Vindication of Goldbach's conjecture
Posted:
Jun 9, 2012 4:56 AM


On 8 juin, 15:08, Count Dracula <Levent.Ki...@navy.mil> wrote: > On Jun 8, 8:27 am, mluttgens <lutt...@gmail.com> wrote: > > > Anyhow, the "trick" is mathematically correct and vindicates the > > conjecture. > > Marcel Luttgens > > What if there is an even integer k > 4 such that in all sums k = a + > b, where > a and b are odd, either a or b is nonprime? If you can provide a proof > precluding > this possibility you will have proved Goldbach's conjecture. > > Best, > Levent > >
Thank you.
In P, the number 26 = 3+23, 5+21, 7+19, 9+17, 11+15, 13+13, 15+11, 17+9, 19+7, 21+5 and 23+3, all the terms coming from the successive uneven numbers of S and S' from 3 to 23, where 23 = 26  3. As S and S' contain all the prime numbers inferior or equal to 263 , the even number 26 is necessarily the sum of two primes. Let?s note that it is not necessary to indentify those primes. Knowing that they exist in S and S? is enough.. This applies mutatis mutandi to any even integer
Marcel Luttgens

