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Re: Vindication of Goldbach's conjecture
Posted:
Jun 9, 2012 4:56 AM
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On 8 juin, 15:08, Count Dracula <Levent.Ki...@navy.mil> wrote:
> On Jun 8, 8:27 am, mluttgens <lutt...@gmail.com> wrote:
>
> > Anyhow, the "trick" is mathematically correct and vindicates the
> > conjecture.
> > Marcel Luttgens
>
> What if there is an even integer k > 4 such that in all sums k = a +
> b, where
> a and b are odd, either a or b is nonprime? If you can provide a proof
> precluding
> this possibility you will have proved Goldbach's conjecture.
>
> Best,
> Levent
>
>
Thank you.
In P, the number 26 = 3+23, 5+21, 7+19, 9+17, 11+15, 13+13, 15+11,
17+9, 19+7, 21+5 and 23+3, all the terms coming from the successive
uneven numbers of S and S' from 3 to 23, where 23 = 26 - 3.
As S and S' contain all the prime numbers inferior or equal to 26-3 ,
the even number 26 is necessarily the sum of two primes.
Let?s note that it is not necessary to indentify those primes. Knowing
that they exist in S and S? is enough..
This applies mutatis mutandi to any even integer
Marcel Luttgens
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