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Topic: borderline of finite with infinite Chapt13.40085 Maxwell Equations
placing demands on mathematics #631 New Physics #751 ATOM TOTALITY 5th ed

Replies: 54   Last Post: Jun 29, 2012 1:48 PM

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 plutonium.archimedes@gmail.com Posts: 18,572 Registered: 3/31/08
120^291 (1.1*10^605) as infinity borderline Chapt13.40085 Maxwell
Equations placing demands on mathematics #646 New Physics #766 ATOM TOTALITY
5th ed

Posted: Jun 18, 2012 5:51 PM

On Jun 18, 4:00 pm, Transfer Principle <david.l.wal...@lausd.net>
wrote:
> On Jun 18, 11:02 am, Archimedes Plutonium
>
> <plutonium.archime...@gmail.com> wrote:

> > So, does there exist a number that is between 10^603 and 10^604 that
> > is a [power] of 120, that is 120^n [...]

>
> No, no such number exists. The powers of closest to this range are:
>
> 120^290 = 9.174055302...*10^602
> 120^291 = 1.100886636...*10^605
>
> As 291 is a multiple of three, 120^291 is a perfect cube -- its
> cube root would be 120^97.

Thanks Transfer, I had some inkling that the gap was going to be
larger than 10^603
by loosening the reins over floor pi but did not expect it to go out
to 10^605. If it
is not too difficult, can you compute the perfect cube 120^n
immediately below
120^291? Maybe it is 10^600???

If I have to accept 120^291, that leaves me a problem of reconciling
pi for the
sphere pseudosphere area. They have to be equal in area at infinity.
So if infinity
starts at 120^291, I would be required to use pi at 10^-605

Pi = 3.
1415926535 8979323846 2643383279 5028841971 6939937510  : 50
5820974944 5923078164 0628620899 8628034825 3421170679  : 100
8214808651 3282306647 0938446095 5058223172 5359408128  : 150
4811174502 8410270193 8521105559 6446229489 5493038196  : 200
4428810975 6659334461 2847564823 3786783165 2712019091  : 250
4564856692 3460348610 4543266482 1339360726 0249141273  : 300
7245870066 0631558817 4881520920 9628292540 9171536436  : 350
7892590360 0113305305 4882046652 1384146951 9415116094  : 400
3305727036 5759591953 0921861173 8193261179 3105118548  : 450
0744623799 6274956735 1885752724 8912279381 8301194912  : 500
9833673362 4406566430 8602139494 6395224737 1907021798  : 550
6094370277 0539217176 2931767523 8467481846 7669405132  : 600
0005681271 4526356082 7785771342 7577896091 7363717872  : 650

I would be required to use the --00056--

So say we had a sphere of volume 1, would we have a pseudosphere
volume
of exactly 1/2 and both areas equal by using pi at those 605 digits
and where infinity is this 1.1 x 10^605.

Previously I was counting on the three zero digits to allow for the
pseudosphere
to catch up but now I need to tag on that extra two digits of 56.

The trouble here in mathematics, is that we have no computer or
formula to
compute the area and volume of pseudosphere in the 10^603 to 10^605
range.

I need to know if the pseudosphere area catches up and matches the
attendant
sphere in that range.

Archimedes Plutonium
http://www.iw.net/~a_plutonium
whole entire Universe is just one big atom
where dots of the electron-dot-cloud are galaxies

Date Subject Author
6/15/12 plutonium.archimedes@gmail.com
6/15/12 hanson
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6/19/12 plutonium.archimedes@gmail.com
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6/19/12 Transfer Principle
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6/21/12 Jos Bergervoet
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6/25/12 narasimham
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6/29/12 quasi
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6/17/12 plutonium.archimedes@gmail.com
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6/17/12 Transfer Principle
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6/18/12 KBH
6/18/12 KBH
6/18/12 KBH
6/18/12 plutonium.archimedes@gmail.com
6/18/12 plutonium.archimedes@gmail.com
6/18/12 plutonium.archimedes@gmail.com
6/18/12 plutonium.archimedes@gmail.com
6/18/12 Transfer Principle
6/18/12 plutonium.archimedes@gmail.com
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6/18/12 Bob Masta
6/17/12 Transfer Principle