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Topic: Vindication of Goldbach's conjecture
Replies: 74   Last Post: Aug 9, 2012 6:50 PM

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 mluttgens Posts: 80 Registered: 3/3/11
Re: Vindication of Goldbach's conjecture
Posted: Jun 20, 2012 10:34 AM
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On 17 juin, 20:17, quasi <qu...@null.set> wrote:
> On Sun, 17 Jun 2012 02:20:49 -0700 (PDT), mluttgens
>
> <lutt...@gmail.com> wrote:

> >83749105938571693046 = 157 + 83749105938571692889
> >                     = 277 + 83749105938571692769
> >                     = 283 + 83749105938571692763
> >                     = 487 + 83749105938571692559
> >etc... etc... etc...

>
> Notice that 157 is the _smallest_ prime that works.
>
> Thus, the following attempts all fail:
>
> 83749105938571693046 = 3 + 83749105938571693043
>                        5 + 83749105938571693041
>                        7 + 83749105938571693039
>                        11 + 83749105938571693035
>                        13 + 83749105938571693033
>                        17 + 83749105938571693029
>                        ...
>                        151 + 83749105938571692895
>
> So by trial and error, you find that 157 works, but you didn't
> know that before you checked the other summand. So how did
> you know in advance that some prime was going to work?
>
> To prove Goldbach's Conjecture, you have to show, for the
> general even n > 4, not a just a particular case, that a pair
> of odd primes exists whose sum is n. That you haven't done.
>
> Note: "mutatis mutandi" is not a valid principle of
> mathematical reasoning.
>
> quasi
>
>

It was easy to show that the even number 26 is the sum of two primes:

26 = 3+23, 7+19, 13+13, 19+7 and 23+3.

Let's call those sums Goldbach's sums.
The number 26 has thus 5 Goldbach's sums. Hence, the number 26
vindicates Goldbach's conjecture.

In order to falsify the conjecture, one should need to show that some
even number can't be the sum of two primes.

Hereafter are the numbers n of Goldbach's sums for increasing even
numbers N:

N n
_ _

50 8
100 12
500 26
1000 56
5000 152
10000 254
50000 900
100000 1628

Clearly, when N increases, the number of Goldbach's sums also
increases.
Perhaps could somebody finds a formula linking N and n.
The given example shows that n cannot decrease from some value of N
and eventually becomes zero.
Thus, it vindicates Goldbach's conjecture.

Marcel Luttgens

Date Subject Author
6/6/12 mluttgens
6/6/12 Brian Q. Hutchings
6/6/12 GEIvey
6/7/12 Richard Tobin
6/8/12 mluttgens
6/8/12 Count Dracula
6/9/12 mluttgens
6/9/12 Brian Q. Hutchings
6/9/12 mluttgens
6/25/12 GEIvey
6/9/12 Richard Tobin
6/9/12 mluttgens
6/9/12 Richard Tobin
6/9/12 Brian Q. Hutchings
6/9/12 Brian Q. Hutchings
6/14/12 mluttgens
6/14/12 Horand.Gassmann@googlemail.com
6/16/12 mluttgens
6/16/12 Frederick Williams
6/20/12 mluttgens
6/20/12 Rick Decker
6/21/12 mluttgens
6/21/12 Frederick Williams
6/21/12 mluttgens
6/21/12 Horand.Gassmann@googlemail.com
6/22/12 mluttgens
6/22/12 Horand.Gassmann@googlemail.com
6/22/12 mluttgens
6/22/12 Brian Q. Hutchings
6/22/12 Horand.Gassmann@googlemail.com
6/25/12 Michael Stemper
6/26/12 mluttgens
6/26/12 Frederick Williams
6/28/12 Michael Stemper
7/19/12 mluttgens
7/19/12 Timothy Murphy
7/19/12 mluttgens
7/19/12 Gus Gassmann
7/20/12 mluttgens
8/1/12 Tim Little
8/4/12 mluttgens
8/4/12 Frederick Williams
8/6/12 mluttgens
8/6/12 gus gassmann
8/6/12 Brian Q. Hutchings
8/9/12 Pubkeybreaker
7/19/12 J. Antonio Perez M.
7/20/12 mluttgens
6/25/12 Michael Stemper
6/25/12 Thomas Nordhaus
6/16/12 Horand.Gassmann@googlemail.com
6/17/12 mluttgens
6/17/12 quasi
6/18/12 Count Dracula
6/18/12 quasi
6/19/12 Count Dracula
6/19/12 quasi
6/20/12 mluttgens
6/22/12 Michael Stemper
6/22/12 mluttgens
6/22/12 Robin Chapman
6/22/12 Michael Stemper
6/23/12 mluttgens
6/22/12 Richard Tobin
6/22/12 Richard Tobin
6/25/12 Richard Tobin
6/25/12 Michael Stemper
6/14/12 Count Dracula
6/21/12 Luis A. Rodriguez
6/21/12 Brian Q. Hutchings
6/21/12 mluttgens
6/25/12 GEIvey
6/20/12 J. Antonio Perez M.
6/19/12 Madhur
6/19/12 Brian Q. Hutchings

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