Thanks for your input, everyone. I got similar responses about renaming the function from the folks in my own department. Mike Ecsedy, Joel Barlow HS, Redding, CT
________________________________ From: Alan Lipp <email@example.com> To: Michael Ecsedy <firstname.lastname@example.org> Cc: AP Calculus <email@example.com> Sent: Friday, September 14, 2012 6:18 PM Subject: Re: [ap-calculus] Domain of functions question
I think confusion can arise if you are not clear what function you refer to. As you define f its domain is [-2, 1]]. You are defining a new function as a transformation of f, that is g(x) = f(x-1) + 1. The domain of f remains the same, but the domain of g is [-1, 2] since these are the input values for the independent variable of g that are allowable.
Alan Lipp Williston Northampton School
On Sep 14, 2012, at 8:54 AM, Michael Ecsedy wrote: