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Re: [apcalculus] Need help plaease on 2008 BC MC # 17
Posted:
Sep 20, 2012 4:48 PM


NOTE: This apcalculus EDG will be closing in the next few weeks. Please sign up for the new AP Calculus Teacher Community Forum at https://apcommunity.collegeboard.org/gettingstarted and post messages there.  On Sep 20, 2012, at 1:18 PM, Qayumi, Enayat wrote:
>  > If h is a differentiable function and f(x) = h (x^2  3) > > Why is the f'(x) = 2x h'(x^23) which will give the correct answer once you plug in x = 2 > > And Not > > f'(x) = h' (x^2  3) + h (2x)
There is a difference between f(x)=h(x)*(x^23) and f(x)=h(x^23). In the first case f is given as the product of a function named "h" and a second function (lets call it "g") with g(x) = x^2  3. so f(x) = h(x) * g(x). In the second case f is given as the composite of h following g. So f(x) = h(g(x)). Try the Chain Rule instead of the Product Rule.
Sincerely,
Richard Sisley  To search the list archives for previous posts go to http://lyris.collegeboard.com/read/?forum=apcalculus



