
Re: An Algebra 2 Test
Posted:
Sep 29, 2012 6:50 AM



What can I say? I didn't know the "hidden trick".
Bob Hansen
On Sep 29, 2012, at 1:23 AM, Wayne Bishop <wbishop@calstatela.edu> wrote:
> My guess is that the approach Dave had in mind was more obvious: > a^2  (a1)^2 = (a  (a1)) (a + (a1)) = (1)(2a  1) > > Wayne > > At 08:36 PM 9/28/2012, Robert Hansen wrote: >> a^2  (a1)^2 = a^2  (a^2  2a + 1) = 2a  1 = 13.04822... >> >> This is a very good point, work the algebra FIRST. I wonder how many algebra teachers are even capable of concocting such a problem? Working backwards and making sure that 2*a doesn't require any more than single digit math (no digit greater than 4). I have to think about this. This works well with large integers as well, with the same condition on the digits. >> >> Lou, what do you say to problems like this with regards to our prior art discussion? >> >> Ha, calculators are allowed. Calculators with 70 digits of precision I suppose.:) >> >> Bob Hansen >> >> On Sep 28, 2012, at 5:51 PM, "Dave L. Renfro" <renfr1dl@cmich.edu> wrote: >> >> > Robert Hansen wrote: >> > >> > http://mathforum.org/kb/message.jspa?messageID=7897638 >> > >> >> I want to try something different. I want everyone to contribute >> >> problems for a hypothetical algebra 2 exam. You can contribute >> >> just topics if you wish though I would like see examples as well. >> >> I am going with algebra 2 rather than algebra 1 because I think >> >> the line is more well defined. >> > >> > I only have a few moments before I need to leave to tutor >> > someone, but here's a somewhat silly one off the top of >> > my head: >> > >> > Determine the exact value of a^2  b^2 if >> > >> > a = 7.0241132301442003123012230341430201 >> > b = 6.0241132301442003123012230341430201 >> > >> > Calculators are allowed. >> > >> > Dave L. Renfro

