In article <firstname.lastname@example.org>, stoneboy <email@example.com> wrote:
> .... > 1+a+b+c+ab+bc+ca+abc > > .... How do I go about deciphering how to group and > factor the original equation above....
jdmgt has shown you how this one can be handled. As a general rule for expressions with more than one variable, it's often a good idea to concentrate on one variable at a time. Thinking of this example in terms of c gives
c(ab + a + b + 1) + (ab + a + b + 1)
= (c + 1)(ab + a + b + 1).
Then think of the factor (ab + a + b + 1) interms of b:
b(a + 1) + (a + 1) etc.
A similar trick sometimes works with expressions of higher degree.