Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
Drexel University or The Math Forum.
|
|
|
|
RE: [ap-calculus] larson pg 137 exercise 69
Posted:
Oct 17, 2012 1:39 PM
|
|
NOTE:
This ap-calculus EDG will be closing in the next few weeks. Please sign up for the new AP Calculus
Teacher Community Forum at https://apcommunity.collegeboard.org/getting-started
and post messages there.
------------------------------------------------------------------------------------------------
Dwayne,
Start with
(I) x^2 - kx = 5x - 4 (the y-values must be the same at the point of tangency)
and
(II) 2x - k = 5 (the derivatives must also be the same at the points of tangency).
Then solve for k in (II).
(IIa) k = 2x - 5
Substitute into (I)
(III) x^2 - (2x-5)*x = 5x - 4
Simplify
x^2 - 2x^2 + 5x = 5x - 4
x^2 - 4 = 0
Factor
(x - 2)(x + 2) = 0
x = 2, -2
We are not done! Substitute back into (IIa) to solve for k.
k = 2(2) - 5 = -1
k = 2(-2) - 5 = -9
It seems that you just forgot to solve for k after finding x. Let me know if you have any questions!
Sincerely,
Mat
-----Original Message-----
From: Dwayne Wellington [mailto:mrdw27@gmail.com]
Sent: Wednesday, October 17, 2012 8:29 AM
To: AP Calculus
Subject: [ap-calculus] larson pg 137 exercise 69
NOTE:
This ap-calculus EDG will be closing in the next few weeks. Please sign up for the new AP Calculus Teacher Community Forum at https://apcommunity.collegeboard.org/getting-started
and post messages there.
------------------------------------------------------------------------------------------------
Good morning, I was working on exercise 69 from Larson early Transcendentals and am missing the key to answering the question.
Find the value of k such that the line is tangent to the graph of the function.
(function) f(x) = x^2 - kx (line) y = 5x -4
the answers are x= -1, -9 but I can't seem to get that when I work out the problem. Thank you for the assistance in advance.
---
To search the list archives for previous posts go to http://lyris.collegeboard.com/read/?forum=ap-calculus
______________________________________________________________________
This email has been scanned by the Symantec Email Security.cloud service.
For more information please visit http://www.symanteccloud.com ______________________________________________________________________
______________________________________________________________________
This email has been scanned by the Symantec Email Security.cloud service.
For more information please visit http://www.symanteccloud.com
______________________________________________________________________
---
To search the list archives for previous posts go to
http://lyris.collegeboard.com/read/?forum=ap-calculus
|
|
|
|
