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Re: Reciprocals of integers summing to 1
Posted:
Nov 16, 2012 9:10 AM
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On Thursday, November 15, 2012 11:39:57 PM UTC-6, Charlie-Boo wrote:
> On Nov 16, 12:21 am, William Elliot <ma...@panix.com> wrote:
>
> > On Thu, 15 Nov 2012, Charlie-Boo wrote:
>
> > > For each n, what are the solutions in positive integers (or in
>
> > > integers) to (1/X1)+(1/X2) + . . . + (1/Xn)=1 ?
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> >
>
> > x1 = x2 =..= x_n = n
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>
>
> But there is also 1/2 + 1/3 + 1/6 = 1. I am asking for all solutions.
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>
>
> C-B
Here's another
1/2 + 1/3 + 1/7 + 1/42 = 1.
don
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