
Re: Reciprocals of integers summing to 1
Posted:
Nov 16, 2012 9:10 AM


On Thursday, November 15, 2012 11:39:57 PM UTC6, CharlieBoo wrote: > On Nov 16, 12:21 am, William Elliot <ma...@panix.com> wrote: > > > On Thu, 15 Nov 2012, CharlieBoo wrote: > > > > For each n, what are the solutions in positive integers (or in > > > > integers) to (1/X1)+(1/X2) + . . . + (1/Xn)=1 ? > > > > > > x1 = x2 =..= x_n = n > > > > But there is also 1/2 + 1/3 + 1/6 = 1. I am asking for all solutions. > > > > CB
Here's another
1/2 + 1/3 + 1/7 + 1/42 = 1.
don

