Thank you very much for your kindly help, and sorry for no feedback for such long time. I have some questions about this problem. If possible, please give me help. Thanks in advance.
In the following, I will do the calculation according to your comments. Please tell me whether I am wrong or not.
On 2012-08-18 9:39, Rich Ulrich wrote: > On Fri, 17 Aug 2012 01:49:39 -0400, Rich Ulrich > <firstname.lastname@example.org> wrote: > > [snip, a bunch] >> >> I *think* what follows is a safe, conservative procedure -- >> The minimum, proper fitted equation will show no less error >> than the measurement error. For that, the pooled SD is > > Keep in mind that the MS-residual is an estimate of the variance > (which is the square of the standard deviation) of the residual. > > When I was learning to use regression, it helped me when > I realized that fact. Then I started making a point of noticing that > variance, and taking the square root ... just to make sure that > I was still analyzing the same set that I thought I was, and that > nothing was going strange. > > >> about 42, or the "Mean-square-residual" is the square of >> 42, with 10 d.f. Take the Mean square for Regression from >> the 5-point regression and divide it by *this* residual, >> instead of the computed residual, to get the safe F-test. > > Oops! slligh correction -- For the 5 point regression, each > point is the average of three measures. The SD of the *3* > taken separately is 42; the SD of the average is, naturally, > the raw SD divided by the square root of N, or sqrt(3). > Or - the MS is not 42-squared, but is 42-squared, divided > by 3. >