In article <firstname.lastname@example.org>, WM <email@example.com> wrote:
> On 19 Nov., 01:15, William Hughes <wpihug...@gmail.com> wrote: > > On Nov 18, 8:04 pm, Vurgil <Vur...@arg.erg> wrote: > > > > > > > > > > > > > In article > > > <a924b8a3-c051-4e91-a088-c9ee5167a...@d17g2000vbv.googlegroups.com>, > > > > > WM <mueck...@rz.fh-augsburg.de> wrote: > > > > Matheology 154: Consistency Proof! > > > > > > The long missed solution of an outstanding problem came from a > > > > completely unexpected side: Social science proves the consistency of > > > > matheology by carrying out a poll. > > > > > > As recently reported (see matheology 152) > > > >http://www.hs-augsburg.de/~mueckenh/KB/Matheology.pdf > > > > mathematics and matheology lead to different values of the continued > > > > fraction > > > > > > 1/((((((10^0)/10)+10^1)/10)+10^2)/10)+ = 0 (Cauchy) > > > > 1/((((((10^0)/10)+10^1)/10)+10^2)/10)+ > 1 (Cantor) > > > > > It is not at all clear that these expressions represent any continued > > > fraction at all. > > > > One of the problems with attempting any discussion with WM > > is the fact that he is unable or unwilling to define anything. > > I am convinced that you are intelligent enough to understand above > expressions. > > > The idea that he is introducing complications > > because when he is clear it is obvious he is wrong is > > hard to resist. > > That is my impression of your reaction. But in oder to test it, here > is the complete representation of the continued fraction C: > > C = ((...((((((10^0)/10)+10^1)/10)+10^2)/10)+... +)10^n/10)+... > > Now take the reciproce and find 1/C = 0 or 1/C > 1? Which one is the > correct value?
Any such allegedly infinite continued fraction should be representable as a sequence of truncated continued fractions: C_0 = a_0 C_1 = a_0 + 1/a_1 C_2 = a_0 + 1/(a_1 + 1/a_2) C_3 = a_0 + 1/(a_1 + 1/(a_2 + 1/a_3)) and so on, with C as the limit, provided it exists.
But WM's 'C' does not seem to be capable of any such analysis, and thus is not a continued fraction, at least in any usual sense, at all, at all.