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Re: What am I missing?
Posted:
Nov 23, 2012 1:13 AM


"Greg Heath" <heath@alumni.brown.edu> wrote in message <k8m4qf$8de$1@newscl01ah.mathworks.com>... > % help rank > % > % rank Matrix rank. > % rank(A) provides an estimate of the number of linearly > % independent rows or columns of a matrix A. > > >>A1= round(rand(1,5)) > A2 = 1A1
Multiply a vector (here A1) by (1) is a linear operator, however adding 1 to a vector is not.
Thus A2 is linear independent to A1. (unless if A1 is a constant vector).
Bruno



