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Nick
Posts:
48
Registered:
4/12/08


Re: Algebra question
Posted:
Nov 23, 2012 4:26 AM


On 23/11/2012 05:19, R wrote: > Hi, > > I read in a stats textbook that this equation: > > [y*theta^(y1)](ny)*(theta^y)(1theta)^(ny1) > > can be simplified to: > > [y*theta^(y1)]*[(1theta)^(ny1)]*(yn*theta) > > Could someone please show me the steps necessary to go from the first equation to the second equation? > > Any tips would be much appreciated. > > R > Doesn't appear to be true. For instance if theta = 1 and y <> 0 the second equation is 0 where as the first isn't.


Date

Subject

Author

11/23/12


R

11/23/12


Nick

11/23/12


R

11/23/12


Nick

11/23/12


R


