Drexel dragonThe Math ForumDonate to the Math Forum



Search All of the Math Forum:

Views expressed in these public forums are not endorsed by Drexel University or The Math Forum.


Math Forum » Discussions » sci.math.* » sci.math.independent

Topic: PREDICATE CALCULUS 2
Replies: 23   Last Post: Nov 29, 2012 1:13 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Graham Cooper

Posts: 4,237
Registered: 5/20/10
Re: PREDICATE CALCULUS 2
Posted: Nov 27, 2012 9:29 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

>
> {(Y1,Y2)|r(X,Y1)^r(X,Y2)} C {(Y1,Y2)|r(X,Y1)^r(X,Y2)->Y1=Y2}
> DETECTING r is a FUNCTION without QUANTIFIERS!
>


This simplifies to..

{(Y1,Y2) | r(X,Y1)^r(X,Y2)} C {(Y,Y) | r(X,Y)}

which simply guarantees only 1 Y value for any X value.

So it switches from Quantifier ALL(X) P(...) HOLDS
to ALL VALUES OF X SATISFYING { X | P(...) }

which is a different type of result, a SET
but SET1 C SET2
then returns the same Boolean type as Quantifier ALL(X)


Herc




Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© Drexel University 1994-2014. All Rights Reserved.
The Math Forum is a research and educational enterprise of the Drexel University School of Education.