Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: Numerical expression
Replies: 6   Last Post: Nov 28, 2012 3:16 AM

 Messages: [ Previous | Next ]
 Massimo Posts: 2 Registered: 11/25/12
Re: Numerical expression
Posted: Nov 28, 2012 3:16 AM

news:k91u1k\$5k8\$1@smc.vnet.net...
> ((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) + 4 (23)^(1/2))^(1/
> 3))/(3)^(1/2)
> this comes out to
> (2*(9*Sqrt[3] + 4*Sqrt[23])^(1/3))/Sqrt[3]
>
> (2*(9*Sqrt[3] + 4*Sqrt[23])^(1/3))/Sqrt[3]//N
> gives
> 3.76887
> So it's not 1.

Thank you all for your anwers.

I was wrong with a minus sign. The correct expression is:

((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) - 4 (23)^(1/2))^(1/
3))/(3)^(1/2)

With the RealOnly package I get the Real result that I was searching for.

FullSimplify[((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) -
4 (23)^(1/2))^(1/3))/(3)^(1/2)] == 1

Now I ask you how to get the same result using online WolframAlpha.

Thanks again.

__________ Informazioni da ESET Smart Security, versione del database delle firme digitali 7736 (20121127) __________

Il messaggio è stato controllato da ESET Smart Security.

www.nod32.it

Date Subject Author