Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: Numerical expression
Replies: 6   Last Post: Nov 28, 2012 3:16 AM

 Messages: [ Previous | Next ]
 Dana DeLouis Posts: 107 Registered: 12/14/08
Re: Numerical expression
Posted: Nov 28, 2012 3:16 AM

> ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2)

Hi. Just to add to the others, if we "Assume" the following

k = (9*Sqrt[3] + 4*Sqrt[23])^ (1 / 3) ;

// Or...
k=k//FullSimplify
Sqrt[1/2 (13+Sqrt[69])]

Then what you have is:

(k+k) / Sqrt[3.]
3.76887

// Which matches what others have mentioned:

For this to equal 1, then k would have to equal

Sqrt[3] / 2

Perhaps your equation for the k part is off a little. ??

= = = = = = = = = =
HTH :>)
Dana DeLouis
Mac & Mathematica 8
= = = = = = = = = =

On Sunday, November 25, 2012 11:29:24 PM UTC-5, Massimo wrote:
> How could I handle in Mathematica this expression?
>
>
>
> ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2)
>
>
>
> With a lot of trouble I have found out that is equal 1,
>
> but how to get it with Mathematica?
>
>
>
> Thanks very much.
>
>
>
>
>
>
>
> __________ Informazioni da ESET Smart Security, versione del database =

delle firme digitali 7729 (20121125) __________
>
>
>
> Il messaggio =EF=BF=BD stato controllato da ESET Smart Security.
>
>
>
> www.nod32.it

Date Subject Author