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Topic: Matrices of rank at least k
Replies: 12   Last Post: Nov 29, 2012 1:15 PM

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Posts: 289
Registered: 5/23/11
Re: Matrices of rank at least k
Posted: Nov 28, 2012 6:18 PM
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29.11.2012 1:05, quasi wrote:
> An m x n matrix A has rank <= k
> iff every (k+1) x (k+1) submatrix of A has determinant 0,
> iff the sum of the squares of the determinants of all
> (k+1) x (k+1) submatrices of A has determinant 0,

That sounds correct, and finishes the proof. Thanks:)


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