Kaba
Posts:
289
Registered:
5/23/11


Re: Matrices of rank at least k
Posted:
Nov 28, 2012 6:18 PM


29.11.2012 1:05, quasi wrote: > An m x n matrix A has rank <= k > > iff every (k+1) x (k+1) submatrix of A has determinant 0, > > iff the sum of the squares of the determinants of all > (k+1) x (k+1) submatrices of A has determinant 0,
That sounds correct, and finishes the proof. Thanks:)
 http://kaba.hilvi.org

