The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » Math Topics »

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: expand my expression
Replies: 1   Last Post: Dec 1, 2012 11:32 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]

Posts: 132
Registered: 11/27/12
Re: expand my expression
Posted: Dec 1, 2012 11:32 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

You need to be a lot more careful how you write things. By "3sqrt x" do you mean "cube root x"? What you have written would normally be interpreted as "3 times the square root of x" or 3x^(1/2). If it were than, log(3x^(1/2))= log(3)+ (1/2)log(x). If you mean cube root of x, x^(1/3) then log(x^(1/3)= (1/3)log(x).

And you need parentheses. It is not clear if "log3 x- 4" means log_3(x- 4) or log_3(x)- 4. (I am assuming that
"3" is the base of the logarithm. log_3(x) is a better way to show that.

Assuming you mean log_3(x^(1/3)/81) then it is, indeed log_3(x^(1/3)- log_3(3^4)= (1/3)log_3(x)- 4.

Date Subject Author
Read expand my expression
Jason R
Read Re: expand my expression

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.