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Math Forum » Discussions » Math Topics » alt.algebra.help.independent

Topic: expand my expression
Replies: 1   Last Post: Dec 1, 2012 11:32 AM

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grei

Posts: 37
Registered: 11/27/12
Re: expand my expression
Posted: Dec 1, 2012 11:32 AM
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You need to be a lot more careful how you write things. By "3sqrt x" do you mean "cube root x"? What you have written would normally be interpreted as "3 times the square root of x" or 3x^(1/2). If it were than, log(3x^(1/2))= log(3)+ (1/2)log(x). If you mean cube root of x, x^(1/3) then log(x^(1/3)= (1/3)log(x).

And you need parentheses. It is not clear if "log3 x- 4" means log_3(x- 4) or log_3(x)- 4. (I am assuming that
"3" is the base of the logarithm. log_3(x) is a better way to show that.

Assuming you mean log_3(x^(1/3)/81) then it is, indeed log_3(x^(1/3)- log_3(3^4)= (1/3)log_3(x)- 4.
Date Subject Author
11/30/12
Read expand my expression
Jason R
12/1/12
Read Re: expand my expression
grei

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