quasi
Posts:
9,076
Registered:
7/15/05
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Re: From Fermat little theorem to Fermat Last Theorem
Posted:
Dec 2, 2012 6:26 AM
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quasi wrote:
>John Jens wrote:
>
>>Finished !!!!!!!!! :)
>>
>>http://primemath.wordpress.com/
>
>You're an idiot.
>
>Several responders have alerted you to the fact that your
>proof is fatally flawed, and yet you obliviously post
>proof after proof, all with the same blatant error.
>
>Your proof fails almost right away. I'll quote from your
>latest version:
>
>>Fermat?s little theorem states that if p is a prime number,
>>then for any integer a, the number a^p is an integer
>>multiple of p.
Still another error above ...
Presumably you meant to say
"the number a^p - a is an integr multiple of p"
rather than
"the number a^p is an integr multiple of p".
Of course that error was probably just a typo, and easily
corrected.
As has been pointed out to you several times, the irreparable
error is your claimed inequality a < p.
>> a^p = a(mod p)
>
>However Fermat's little Theorem doesn't force a < p.
>
>For example, using a = 4, p = 3, we have
>
> a^p = a (mod p)
>
>but a is not less than p.
>
>>Assume that a,b,c naturals and p prime and
>>
>> 0 < a <= b < c
>
>Ok so far.
>
>> and a < p
>
>Stop right there -- you can't justify a < p.
>
>Moreover, there's no repair -- your proof is dead.
quasi
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