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Re: No Putnam spoilers please
Posted:
Dec 5, 2012 12:24 AM
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On Dec 4, 9:48 pm, William Elliot <ma...@panix.com> wrote: > > phi(13) = 12; > 5^2012 = 5^(12 * 168 + 6) = 5^6 = 25^3 = (-1)^3 = -1 = 12 (mod 13)
Actually, 5^2012 = 1 (mod 13).
5^2 = -1 (mod 13) 5^4 = (-1)^2 = 1 (mod 13) 5^2012 = 5^(4*503) = (5^4)^503 = 1^503 = 1 (mod 13)
Your error was in your first step: 2012 = 12*167 + 8.
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