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Re: Vector definition using variables
Posted:
Dec 5, 2012 12:46 PM


"Matt " <mathieu.horsky@gmail.com> wrote in message news:k9nrj4$nrs$1@newscl01ah.mathworks.com... > Hello guys, > > I am having the following problem when I want to use the following > function : > >  > tstep=0.1; > final_time=30; > vect1=0:tstep:final_time >  > > So the vector produced should be 1x301 long. Now the problem is that my > tstep value is defined like this : > >  > tstep=((length(time)1))/length(d) >  > > Where time is a 1x301 vector so value for length(time) should be 301, and > d is a 1x330 vector so the value for length(d) should be 330. Therefore > the value for tstep should be (3011)/330=0.909090 > > When I put this above value manually into vect1, it gives me the correct > vector that I am looking for, but I'm using the tstep value given by the > calculation above (using the length function), it doesn't work. It gives > me a 1x34 vector for example.
What do you expect the length of vect1 to be in this scenario? Seems to me the tstep value for your second case is just over 9 times as large as the step for your first case and the endpoints are the same, so the vector should be approximately 1/9 the length. What is 301/9?
Did you intend for final_time to be related somehow to the values in the time variable? That's not what you described.
 Steve Lord slord@mathworks.com To contact Technical Support use the Contact Us link on http://www.mathworks.com



